Declaring an array in C

Junior WebHelper Joined: 08 Feb 2002 Posts: 37

Hi,

I'm trying to create a simple array in a C file. It goes something like this:

Code:

int NCON=89;
/*#define NCON 89*/
char *constel[89] = {
"And Andromedae",
(etc...)
"Vul Vulpeculae",
};

But when I call for constel[number] ( constel[7], for example) I get a null value. The same thing happens with another array I have:

Code:

/*#define NBNDRIES 357*/
int NBNDRIES = 357;
long bndries[4*357] = {
0L, 86400L, 316800L, 84L,
28800L, 52200L, 311400L, 84L,
(etc...)
0L, 86400L, -324000L, 58L,
};

What am I doing so obviously wrong?

Regards,

Kepler

Junior WebHelper Joined: 08 Feb 2002 Posts: 37

I removed the "*" from constel. Now I get the error: excess elements in char array initializer - but I've counted - it's correct.

Regards,

Kepler

Posted: Wed Oct 20, 2004 2:20 pm (19 years, 6 months ago)

Code:

long bndries[4*357] = {

I don't think you can do mathematical operations there.