cannot check the data provided by a form

Junior WebHelper Joined: 27 Jul 2003 Posts: 4

I have a file which processes the data submitted by the form. I want to check whether the data submitted is identical to the data in mysql database so that if it is not the user corrects the form and submits it again. Here is the code which cannot check the data in submitted form:

Code:

<?php
global $HTTP_POST_VARS;
if (isset($HTTP_POST_VARS['mybutton'])) {
$Host = "***";
$DBName = "***";
$TableName = "patientsform";
$Link = mysql_connect ($Host, '***', '***');
if ($Link==false) {
echo mysql_errno().": ".mysql_error()." \n";
}
mysql_select_db ($DBName, $Link);
$Query1 = "SELECT Forename FROM patients WHERE Forename = {$HTTP_POST_VARS['forename']} AND Surname = {$HTTP_POST_VARS['surname']}";
//The query to check the data submitted
$Query = "INSERT INTO $TableName VALUES ('0', '{$HTTP_POST_VARS['forename']}')";
//The query to put the submitted data into the table

if (mysql_query ($Query1, $Link)) {
print "The query1 was successfully executed! \n";

if (mysql_query ($Query, $Link)) {
print "The query was successfully executed! \n";
}
else {
print "The query could not be executed! \n";
echo mysql_errno().": ".mysql_error()." \n";
}

}
else {
print "The query1 could not be executed! \n";
echo mysql_errno().": ".mysql_error()." \n";
}

mysql_close($Link);
} //end of isset function

else {
echo "you must have come here from somewhere else.\n";
}

MEG

Posted: Wed Aug 06, 2003 3:18 pm (20 years, 8 months ago)

Where abouts is the script failing?
any error messages?

Junior WebHelper Joined: 27 Jul 2003 Posts: 4

When i submit the form by writing 'Martin' in the forename area i get this error message
The query1 could not be executed!
1054: Unknown colomn 'Martin' in 'where clause'

Nevertheless, I know that there are 2 rows with the value of Martin in forename field.
????

Posted: Wed Aug 06, 2003 4:27 pm (20 years, 8 months ago)

try putting the forename and surname variables in single quotes