Help with PHP code

Junior WebHelper Joined: 06 Aug 2003 Posts: 1

Hey, I dunno what's wrong, but here's what the error says:

Code:

Parse error: parse error, unexpected '{' in c:\appserv\www\login.php on line 17

Here's my PHP:

Code:

if ($submit = "Login")
{

mysql_connect("JOEYOWNZ", "punkgo", "********") or
die ("Could not connect to database");

mysql_select_db("users") or
dir ("Could not select database");

$_REQUEST=mysql_query("select * from user where username='" . $username . "'")
or die ("cant do it");

while ($row=mysql_fetch_array($_REQUEST)) {
if ( isset( $_POST[ 'password' ] )
{
printf("Successfully Logged In!");
}else{
print("Nope");

}
}
}
?>

Posted: Thu Aug 07, 2003 7:17 am (20 years, 8 months ago)

Couple of things highlighted below = should be ==
and dir should be die

see if that helps

Quote:

if ($submit = "Login")
{
mysql_connect("JOEYOWNZ", "punkgo", "********") or
die ("Could not connect to database");

mysql_select_db("users") or
dir ("Could not select database");

$_REQUEST = mysql_query("select * from user where username='" . $username . "'")
or die ("cant do it");

while ($row=mysql_fetch_array($_REQUEST))
{
if ( isset( $_POST[ 'password' ] )
{
printf("Successfully Logged In!");
}
else
{
print("Nope");
}
}
}

Posted: Thu Aug 07, 2003 2:22 pm (20 years, 8 months ago)

in addition to what Darren said, you should correct the following:

Code:

if ( isset( $_POST[ 'password' ] )

should be

Code:

if ( isset( $_POST[ 'password' ] ) )

Posted: Thu Aug 07, 2003 2:58 pm (20 years, 8 months ago)

well spotted Very Happy

Posted: Fri Aug 08, 2003 3:06 pm (20 years, 8 months ago)

Code:

$_REQUEST = mysql_query("select * from user where username='" . $username . "'")
or die ("cant do it");

$_REQUEST is a special array. you should not change information contained in it by assigning it some other values.